PART I: PHYSICS
SECTION 1 (Maximum Marks: 18)
• This section contains SIX questions.
• Each question has FOUR options
Text Solution
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so
. . . (i)
Now mass defect of N atom = 8 x 1.008665 + 7 x 1.007825 - 15.000109
= 0.1239864 u
So binding energy = 0.1239864 x 931.5 MeV
and mass defect of O atom = 7 x 1.008665 + 8 x 1.007825 - 15.003065
= 0.12019044 u
So binding energy =0.12019044 x 931.5 MeV
So |B 0 - B N |= 0.0037960 x 931.5 MeV .. .. (ii)
from (i) and (ii) we get
R= 3.42 fin.
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The measured masses of the neutron,
and
are 1.008665 u, 1.007825 u, 15.000109 u and 15.003065u, respectively. Given that the radii of both the
and
nuclei are same, 1 u = 931.5MeV/c 2 (c is the speed of light) and e 2 /
= 1.44 MeV fin. Assuming that the difference between the binding energies of
and
is purely due to the electrostatic energy, the radius of either of the nuclei is (1 fin= 10 -15 m) 3.80 fm